Additional Problems 8

Visualizing Chemistry

Problem 8.14
Give IUPAC names for the following substances (red = O, blue = N):

(a)

The ball-and-stick model of a molecule has a 6-membered ring with alternate double bonds. C 1 is bonded to hydroxyl. C 3 is bonded to an isopropyl group.

(b)

The ball-and-stick model of a molecule has a 6-membered ring with alternate double bonds. C 1 is bonded to a carboxylic acid group and C 2 to a nitro group.

Problem 8.15
The following molecular model is that of a carbocation. Draw two resonance structures for the carbocation, indicating the positions of the double bonds.

The ball-and-stick model of a cationic molecule has three six-membered rings fused together.

Problem 8.16
Azulene, an isomer of naphthalene, has a remarkably large dipole moment for a hydrocarbon (μ = 1.0 D). Explain, using resonance structures.

The ball-and-stick model with the electrostatic potential map of azulene. In the structure, a seven-membered ring is fused with a 5-membered ring.

Problem 8.17
Draw the product from reaction of each of the following substances with (1) Br2, FeBr3 and (2) CH3COCl, AlCl3.

(a)

The ball-and-stick model has a benzene ring bonded to an oxygen atom, which is bonded to a methyl group.

(b)

The ball-and-stick model has a benzene ring. C 1 is bonded to an aldehyde group. C 4 is bonded to a methyl group.

Problem 8.18
How would you synthesize the following compound starting from benzene? More than one step is needed.

The ball-and-stick model has a benzene ring. C 1 is bonded to a carboxylic acid group. C 4 is bonded to an amino group.

Problem 8.19
The following compound can’t be synthesized using the methods discussed in this chapter. Why not?

The ball-and-stick model has a toluene ring. C 3 is bonded to an amino group.

Naming Aromatic Compounds

Problem 8.20
Give IUPAC names for the following compounds:

(a)

In a benzene ring, C 1 is bonded to a 5-carbon chain, in which C 1 and C 4 are each bonded to a methyl group.

(b)

In a benzene ring, C 1 and C 3 are bonded to a carboxylic acid group and a bromine atom, respectively.

(c)

In a benzene ring, C 1 is bonded to a bromine atom and C3 and C5 to methyl groups.

(d)

In a benzene ring, C 1 is bonded to a bromine atom and C 2 is bonded to a 3-carbon chain.

(e)

In a benzene ring, C 1 is bonded to a fluorine atom and C2 and C4 are each bonded to a nitro group.

(f)

In a benzene ring, C 1 and C 4 are bonded to an amine group and a chlorine atom, respectively.

Problem 8.21
Draw structures corresponding to the following names:

(a) 3-Methyl-1,2-benzenediamine

(b) 1,3,5-Benzenetriol

(c) 3-Methyl-2-phenylhexane

(d) o-Aminobenzoic acid

(e) m-Bromophenol

(f) 2,4,6-Trinitrophenol (picric acid)

Problem 8.22
Draw and name all possible isomers of the following:

(a) Dinitrobenzene

(b) Bromodimethylbenzene

(c) Trinitrophenol

Problem 8.23
Draw and name all possible aromatic compounds with the formula C7H7Cl.

Problem 8.24
Draw and name all possible aromatic compounds with the formula C8H9Br. (There are 14.)

Structure of Aromatic Compounds

Problem 8.25
Propose structures for aromatic hydrocarbons that meet the following descriptions:

(a) C9H12; gives only one C9H11Br product on substitution of a hydrogen on the aromatic ring with bromine

(b) C10H14; gives only one C10H13Cl product on substitution of a hydrogen on the aromatic ring with chlorine

(c) C8H10; gives three C8H9Br products on substitution of a hydrogen on the aromatic ring with bromine

(d) C10H14; gives two C10H13Cl products on substitution of a hydrogen on the aromatic ring with chlorine

Problem 8.26
Look at the three resonance structures of naphthalene shown in Section 8.9, and account for the fact that not all carbon–carbon bonds have the same length. The C1–C2 bond is 136 pm long, whereas the C2–C3 bond is 139 pm long.

Problem 8.27
Anthracene has four resonance structures, one of which is shown. Draw the other three.

Anthracene has three benzene rings fused to one another in a straight line.

Problem 8.28
Phenanthrene has five resonance structures, one of which is shown. Draw the other four.

Phenanthrene has three benzene rings fused to one another, two of them in a straight line and the third up to the top right..

Problem 8.29
Look at the five resonance structures for phenanthrene (Problem 8.28), and predict which of its carbon–carbon bonds is shortest.

Problem 8.30
Indole is an aromatic heterocycle that has a benzene ring fused to a pyrrole ring. Draw an orbital picture of indole.

(a) How many π electrons does indole have?

(b) What is the electronic relationship of indole to naphthalene?

Indole has a benzene ring fused to a 5-membered ring made of a nitrogen atom and four carbon atoms, in which the two carbons not fused to the benzene ring have a double bond between them.

Problem 8.31
Ribavirin, an antiviral agent used against hepatitis C and viral pneumonia, contains a 1,2,4- triazole ring. Why is the ring aromatic?

Ribavirin has 1,2,4-triazole ring. N 1 is bonded to ribose ring. The carbon at position 3 is bonded to a carbonyl group, which itself is bonded to an amine.

Mechanisms of Electrophilic Substitutions

Problem 8.32
Aromatic iodination can be carried out with a number of reagents, including iodine monochloride, ICl. What is the direction of polarization of ICl? Propose a mechanism for the iodination of an aromatic ring with ICl.

Problem 8.33
The N,N,N-trimethylammonium group, –N(CH3)3, is one of the few groups that is a meta-directing deactivator yet has no electron-withdrawing resonance effect. Explain.

Problem 8.34
Using resonance structures of the intermediates, explain why bromination of biphenyl occurs at ortho and para positions rather than at meta.

Biphenyl has a benzene ring bonded to another benzene ring.

Problem 8.35
Addition of HBr to 1-phenylpropene yields only (1-bromopropyl)benzene. Propose a mechanism for the reaction, and explain why none of the other regioisomer is produced.

Benzene bonded to a three-carbon chain with double bond between C 1 and C 2 reacts with hydrogen bromide to form a product when bromine is added to C1 of the three-carbon chain

Problem 8.36
Propose a mechanism to account for the following reaction:

Benzene bonded to acetyl group at C 1 and a 4-carbon chain with terminal carbon bonded to chlorine reacts with aluminum chloride to form a product.where the 4-carbon chain is cyclized on to the benzene ring

Problem 8.37
Benzyl bromide is converted into benzaldehyde by heating in dimethyl sulfoxide. Propose a structure for the intermediate, and show the mechanisms of the two steps in the reaction.

A two-step reaction shows benzene bonded to a C H 2 B r group being converted to benzene bonded to an aldehyde group.

Reactivity and Orientation of Electrophilic Substitutions

Problem 8.38
Identify each of the following groups as an activator or deactivator and as an o,p-director or m-director:

(a)

The structure of a group where N H (C H 3) 2 is bonded to an open single bond that has a wavy line across it.

(b)

The structure of a group where cyclopentane ring is bonded to an open single bond that has a wavy line across it.

(c)

The structure of a group where O C H 2 C H 3 is bonded to an open single bond that has a wavy line across it.

(d)

A cyclohexane ring bonded to a carbonyl group. The carbonyl carbon is bonded to an open single bond that has a wavy line across it.

Problem 8.39
Predict the major product(s) of nitration of the following substances. Which react faster than benzene, and which slower?

(a) Bromobenzene

(b) Benzonitrile

(c) Benzoic acid

(d) Nitrobenzene

(e) Benzenesulfonic acid

(f) Anisole (methoxybenzene)

Problem 8.40
Rank the compounds in each group according to their reactivity toward electrophilic substitution.

(a) Chlorobenzene, o-dichlorobenzene, benzene

(b) p-Bromonitrobenzene, nitrobenzene, phenol

(c) Fluorobenzene, benzaldehyde, o-xylene

(d) Benzonitrile, p-methylbenzonitrile, p-methoxybenzonitrile

Problem 8.41
Predict the major monoalkylation products you would expect to obtain from reaction of the following substances with chloromethane and AlCl3:

(a) Bromobenzene

(b) m-Bromophenol

(c) p-Chloroaniline

(d) 2,4-Dichloronitrobenzene

(e) 2,4-Dichlorophenol

(f) Benzoic acid

(g) p-Methylbenzenesulfonic acid

(h) 2,5-Dibromotoluene

Problem 8.42
Rank the following aromatic compounds in the expected order of their reactivity toward Friedel–Crafts alkylation. Which compounds are unreactive?

(a) Bromobenzene

(b) Toluene

(c) Phenol

(d) Aniline

(e) Nitrobenzene

(f) p-Bromotoluene

Problem 8.43
What product(s) would you expect to obtain from the following reaction?

(a)

In water, benzene fused to a cyclohexane ring reacts with potassium permanganate to form unknown product(s), depicted by question mark.

Problem 8.44
Predict the major product(s) of the following reactions:

(a)

Chlorobenzene reacts with ethyl chloride in the presence of aluminum trichloride to form unknown product(s), depicted by question mark.

(b)

A compound containg an oxygen atom bonded to two benzene rings reacts with propanoyl chloride in the presence of aluminum trichloride to form unknown product(s), depicted by question mark.

(c)

Benzoic acid reacts with nitric acid in the presence of sulfuric acid to form unknown product(s), depicted by question mark.

(d)

Benzene bonded to N (C H 2 C H 3) 2 reacts with sulfur trioxide in presence of sulfuric acid to form unknown product(s), depicted by question mark.

Organic Synthesis

Problem 8.45
How would you synthesize the following substances starting from benzene or phenol? Assume that ortho- and para-substitution products can be separated.

(a) o-Bromobenzoic acid

(b) p-Methoxytoluene

(c) m-Bromoaniline

Problem 8.46
Starting with benzene as your only source of aromatic compounds, how would you synthesize the following substances? Assume that you can separate ortho and para isomers if necessary.

(a) p-Chloroacetophenone

(b) m-Bromonitrobenzene

(c) o-Bromobenzenesulfonic acid

(d) m-Chlorobenzenesulfonic acid

General Problems

Problem 8.47
Aromatic substitution reactions occur by addition of an electrophile such as Br+ to an aromatic ring to yield an allylic carbocation intermediate, followed by loss of H+. Show the structure of the intermediate formed by reaction of benzene with Br+.

Problem 8.48
The substitution reaction of toluene with Br2 can, in principle, lead to the formation of three isomeric bromotoluene products. In practice, however, only o– and p-bromotoluene are formed in substantial amounts. The meta isomer is not formed. Draw the structures of the three possible carbocation intermediates and explain why ortho and para products predominate over meta products.

Problem 8.49
Look at the following aromatic anions and their linear counterparts, and draw all of the resonance forms for each. What patterns emerge?

(a)

To the left, cycloheptatriene ring with a positive charge at the single-bonded carbon. To the right, a seven-carbon chain with three alternate double bonds. C 7 carries a positive charge.

(b)

To the left, a five-membered ring comprising of a nitrogen anion and four carbons with double bonds between them. To the right, a 4-carbon chain with two alternate double bonds bonded to N-H minus.

Problem 8.50
Compounds called azo dyes are the major source of artificial color in textiles and food. Part of the reason for their intense coloring is the conjugation from an electron-donating group through the diazo bridge (−N=N−) to an electron-withdrawing group on the other side. For the following azo dyes, draw a resonance form that shows how the electron-donating group is related to the electron-withdrawing group on the other side of the diazo bridge. Used curved arrows to show how the electrons are reorganized.

(a)

m methyl orange

(b)

C.I Acid Red 74

Problem 8.51
Draw resonance structures of the intermediate carbocations in the bromination of naphthalene, and account for the fact that naphthalene undergoes electrophilic substitution at C1 rather than C2.

Naphthalene reacts with molecular bromine to form 1-bromonaphthalene.

Problem 8.52
How would you synthesize the following compound from benzene? Assume that ortho and para isomers can be separated.

(a)

A toluene ring with bromine at C 2 and a nitro group at C 4.

Problem 8.53
You know the mechanism of HBr addition to alkenes, and you know the effects of various substituent groups on aromatic substitution. Use this knowledge to predict which of the following two alkenes reacts faster with HBr. Explain your answer by drawing resonance structures of the carbocation intermediates.

Methoxy benzene with ethene group at the para position and nitrobenzene with an ethene at the para position.

Problem 8.54
Phenols (ArOH) are relatively acidic, and the presence of a substituent group on the aromatic ring has a large effect. The pKa of unsubstituted phenol, for example, is 9.89, while that of p-nitrophenol is 7.15. Draw resonance structures of the corresponding phenoxide anions and explain the data.

Problem 8.55
Would you expect p-methylphenol to be more acidic or less acidic than unsubstituted phenol? Explain. (See Problem 8.54)

Problem 8.56
Predict the product(s) for each of the following reactions. In each case, draw the resonance forms of the intermediate to explain the observed regiochemistry.

(a)

Benzene bonded to acetyl group reacts with nitric acid in the presence of sulfuric acid to form unknown product(s), depicted by a question mark.

(b)

Toluene reacts with 2-chloropropane in the presence of aluminum trichloride to form unknown product(s), depicted by a question mark.

(c)

Benzene bonded to a cyano group reacts with C I 2 in the presence of iron trichloride to form unknown products, depicted by a question mark.

(d)

Benzene bonded to a methoxy group reacts with iodine in the presence of copper (2) chloride to form unknown product(s), depicted by a question mark.

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